Answer
the answer is $$1.70 \mathrm{s}$$
Work Step by Step
We can find the time to go through a full 4 rev (using the same equation to solve for a
$\left.\text { new time } t_{2}\right)$ and then subtract the result of part (a) for $t_{1}$ in order to find this answer.
$$
(4 \text { rev) }(2 \pi \text { rad/rev) }=0+\frac{1}{2} (1.5 \mathrm{rad} / \mathrm{s}^{2}) t_{2}^{2} \Rightarrow t_{2}=5.789 \mathrm{s} \text { . }
$$
Thus, the answer is $$5.789 \mathrm{s}-4.093 \mathrm{s} \approx 1.70 \mathrm{s}$$
