Answer
$\alpha=800rev/min^2$
Work Step by Step
We know that the time interval is 60 seconds or 1 minute.
We find the angular acceleration as:
$\alpha=\frac{\Delta\omega}{t}=\frac{(1000rev/min)-(200rev/min)}{1min}=800rev/min^2$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 10 - Rotation - Problems - Page 288: 23c
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