Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 288: 14b

Answer

$4.8\ s$

Work Step by Step

The angular speed is given by $ω_o=10 rev/s$ Angular position $Δθ=60\ rev$ The final angular speed is $ω=15\ rev/s$ From rotational kinematics equations, we have the formula : $\Delta\theta=\frac{1}{2}(\omega_o+\omega)\Delta t$ $\Delta t=\frac{2\Delta\theta}{\omega_o+\omega}$ $\Delta t=\frac{2(60\ rev)}{10\ rev/s +15\ rev/s}$ $\Delta t =4.8\ s$
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