## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 17 - Exercises and Problems - Page 313: 37

#### Answer

The answer is below.

#### Work Step by Step

a) We use the equation for volume to obtain that the volume of the cylinder is $3.14 \times 10^{-2} m^3$. We now use the ideal gas law to find: $n = \frac{pV}{RT} = \frac{(182\times10^5)(3.14 \times 10^{-2})}{(8.314)(293)} = 234.6 \ mol$ b) We find: $V = \frac{nRT}{p}=\frac{235\times8.314\times293}{10^5}=5.7 m^3$

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