Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems - Page 313: 23

Answer

Please see the work below.

Work Step by Step

We know that $v=\sqrt{\frac{3kT}{m}}$ We plug in the known values to obtain: $v=\sqrt{\frac{(3)(1.38\times 10^{-23})(800)}{3.35\times 10^{-27}}}$ $v=3100\frac{m}{s}$
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