Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems: 34

Answer

Please see the work below.

Work Step by Step

We know that $\Delta L=L\alpha \Delta T$ We plug in the known values to obtain: $\Delta L=(5000)(12\times 10^{-6})(40-(-25))$ $\Delta L=3.9Km$
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