Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems: 35

Answer

Please see the work below.

Work Step by Step

We know that $PV=NKT$ This can be rearranged as: $\frac{N}{V}=\frac{P}{kT}$ We plug in the known values to obtain: $\frac{N}{V}=\frac{0.03}{(1.38\times 10^{-23})(2\times 10^6)}$ $\frac{N}{V}=1.1\times 10^{15}\frac{moleucles }{m^3}$
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