Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems: 36

Answer

Please see the work below.

Work Step by Step

We know that $\frac{P_2V_2}{T_2}=\frac{P_1V_1}{T_1}$ This can be rearranged as: $V_2=\frac{T_2P_1V_1}{T_1P_2}$ We plug in the known values to obtain: $V_2=\frac{(273-10)(1.0)(8.0)}{(273+20)(0.65)}$ $V_2=11L$
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