Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 17 - Exercises and Problems: 22

Answer

Please see the work below.

Work Step by Step

We know that $PV=nRT$ This can be rearranged as: $n=\frac{PV}{RT}$ We plug in the known values to obtain: $n=\frac{(10^{-10})(0.001)}{(8.314)(273.15)}$ $n=4.403\times 10^{-17}moles$ Now we can find the number of molecules as $N=nN_A$ $N=(4.403\times 10^{-17})(6.022\times 10^{23})$ $N=2.7\times 10^7 molecules$
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