## Essential University Physics: Volume 1 (3rd Edition)

$r_2 = 6.32 \ m$
We have to find the distance at which the value of the log function will be half of what it is currently. Thus, we find: $.5 = log(\frac{r_2}{r_1}) \\ .5 = log(\frac{r_2}{2})\\r_2 = 6.32 \ m$