Answer
$r_2 = 6.32 \ m$
Work Step by Step
We have to find the distance at which the value of the log function will be half of what it is currently. Thus, we find:
$.5 = log(\frac{r_2}{r_1}) \\ .5 = log(\frac{r_2}{2})\\r_2 = 6.32 \ m$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 14 - Exercises and Problems - Page 263: 65
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