Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems: 39

Answer

a) 280 Hz b) 70 Hz c) 210 Hz

Work Step by Step

a) The next higher frequency is: $140 \times 2 = 280\ Hz$ b) When the string is clamped, the equation changes from $f=\frac{v}{2}$ to $f=\frac{v}{4}$. Thus, we multiply the original fundamental frequency by 1/2 to find: $=140 \times .5 = 70 \ Hz$ c) The next highest frequency is: $=70 \times (2+1)=210\ Hz$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.