Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 263: 48


The proof is below.

Work Step by Step

We know the following: $v = \sqrt{\frac{F}{\mu}}$ We also know that the force varies based on the height of the cable as follows: $ F= \mu y g$ Using substitution, we find: $v = \sqrt{\frac{\mu y g}{\mu}}$ $v =\sqrt{yg}$
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