## Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson

# Chapter 14 - Exercises and Problems - Page 263: 48

#### Answer

The proof is below.

#### Work Step by Step

We know the following: $v = \sqrt{\frac{F}{\mu}}$ We also know that the force varies based on the height of the cable as follows: $F= \mu y g$ Using substitution, we find: $v = \sqrt{\frac{\mu y g}{\mu}}$ $v =\sqrt{yg}$

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