Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 263: 38


a) 4 meters b) 14 Hz

Work Step by Step

a) We find the longest wavelength by simplifying the equation for L: $ \lambda = \frac{2L}{m}=\frac{2\times 2}{1}=4m$ The lowest frequency corresponds to the longest wavelength. Thus: b) $f = \frac{56}{4} = 14\ Hz$
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