Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 263: 47


30.4 meters per second

Work Step by Step

We first must find the value of $\mu$: $\mu = \sqrt{\frac{14}{18^2}}=.04$ Thus, we can find the new velocity. $ v = \sqrt{\frac{F}{\mu}}=\sqrt{\frac{40}{.0432}}=30.4 \ m/s$
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