Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 14 - Exercises and Problems - Page 263: 62

Answer

a) $ I =10^{-5.5}$ b) $I = 10^{-12.5}$

Work Step by Step

We use the equation for intensities to find: a) $65 = 10log(\frac{I}{10^{-12}}) \\ I =10^{-5.5}$ b) $-5 = 10log(\frac{I}{10^{-12}}) \\ I = 10^{-12.5}$
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