# Chapter 8 - Problems - Page 317: 82

His angular velocity when he left the diving board was $3.15~rad/s$

#### Work Step by Step

We can find the final angular velocity: $\omega_f = \frac{(2.00)(2\pi~rad)}{1.33~s} = 9.45~rad/s$ We can use conservation of angular momentum to find the initial angular velocity: $L_0 = L_f$ $I_0~\omega_0 = I_f~\omega_f$ $\omega_0 = \frac{I_f~\omega_f}{I_o}$ $\omega_0 = \frac{(\frac{I_0}{3.00})~(\omega_f)}{I_0}$ $\omega_0 = \frac{\omega_f}{3.00}$ $\omega_f = \frac{9.45~rad/s}{3.00}$ $\omega_f = 3.15~rad/s$ His angular velocity when he left the diving board was $3.15~rad/s$

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