## College Physics (4th Edition)

The new rate of rotation is $1.49~rev/s$
We can use conservation of angular momentum to find the final angular speed: $L_f = L_0$ $I_f~\omega_f = I_0~\omega_0$ $\omega_f = \frac{I_0~\omega_0}{I_f}$ $\omega_f = \frac{I_0~\omega_0}{0.67~I_0}$ $\omega_f = \frac{1.0~rev/s}{0.67}$ $\omega_f = 1.49~rad/s$ The new rate of rotation is $1.49~rev/s$.