College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 8 - Problems - Page 317: 74


The magnitude of the torque is $~50~N \cdot m$

Work Step by Step

The angular impulse is equal to the change in angular momentum. We can use the change in angular momentum to find the torque: $\tau~t = \Delta L$ $\tau = \frac{L_f-L_0}{t}$ $\tau = \frac{(115~kg~m^2/s)-(240~kg~m^2/s)}{2.5~s}$ $\tau = -50~N \cdot m$ The magnitude of the torque is $~50~N \cdot m$.
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