## College Physics (4th Edition)

The angular momentum of the Earth due to rotation about its axis is $~7.04\times 10^{33}~kg~m^2/s$
We can find the angular speed of the earth as it rotates: $\omega = \frac{\Delta \theta}{\Delta t}$ $\omega = \frac{2\pi~rad}{(24)\cdot (3600~s)}$ $\omega = 7.27\times 10^{-5}~rad/s$ We can find the angular momentum of the Earth due to rotation about its axis: $L = I~\omega$ $L = \frac{2}{5}MR^2~\omega$ $L = \frac{2}{5}(5.97\times 10^{24}~kg)(6.37\times 10^6~m)^2~(7.27\times 10^{-5}~rad/s)$ $L = 7.04\times 10^{33}~kg~m^2/s$ The angular momentum of the Earth due to rotation about its axis is $~7.04\times 10^{33}~kg~m^2/s$.