## College Physics (4th Edition)

The magnitude of the angular momentum is $~1.39\times 10^7~kg~m^2/s$
We can express the angular speed in units of rad/s: $350~rpm~\times \frac{2\pi~rad}{1~rev}\times \frac{1~min}{60~s} = 36.65~rad/s$ We can find the angular momentum: $L = I~\omega$ $L = MR^2~\omega$ $L = (5.6\times 10^4~kg)(2.6~m)^2~(36.65~rad/s)$ $L = 1.39\times 10^7~kg~m^2/s$ The magnitude of the angular momentum is $~1.39\times 10^7~kg~m^2/s$.