College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 8 - Problems - Page 317: 75

Answer

The braking torque would have to be applied for a time of $1.6~seconds$

Work Step by Step

The angular impulse is equal to the change in angular momentum. We can use the change in angular momentum to find the time that the torque should be applied: $\tau~t = \Delta L$ $t = \frac{L_f-L_0}{\tau}$ $t = \frac{0-6.40~kg~m^2/s}{-4.00~N \cdot m}$ $t = 1.6~s$ The braking torque would have to be applied for a time of $1.6~seconds$.
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