College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 7 - Problems - Page 262: 9

Answer

The change in the ball's momentum is $-20.0~kg~m/s$

Work Step by Step

We can find the change in velocity: $\Delta v = v_f-v_0 = (-2.0~m/s)-(2.0~m/s) = -4.0~m/s$ We can find the change in the ball's momentum: $\Delta p = m~\Delta v$ $\Delta p = (5.0~kg)(-4.0~m/s)$ $\Delta p = -20.0~kg~m/s$ The change in the ball's momentum is $-20.0~kg~m/s$.
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