## College Physics (4th Edition)

Let the mass of each car be $m$. Let $v_1 = 19~m/s$ be the velocity of one car. Then $v_2 = -19~m/s$ is the velocity of the other car. We can find the total momentum of the system: $m~v_1+m~v_2 = (1300~kg)~(19~m/s)+(1300~kg)~(-19~m/s) = 0$ The magnitude of the total momentum of the system is 0.