College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 7 - Problems - Page 262: 11

Answer

Since the object started from rest, the change in momentum is $100~kg~m/s$

Work Step by Step

We can find the speed after it falls for $3.4~s$: $v_f = v_0+at = 0+(9.80~m/s^2)(3.4~s) = 33.32~m/s$ We can find the momentum: $p = mv = (3.0~kg)(33.32~m/s) = 100~kg~m/s$ Since the object started from rest, the change in momentum is $100~kg~m/s$.
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