## College Physics (4th Edition)

The average force exerted on the bird during the collision is $6.64~N$
We can find the change in velocity: $\Delta v = v_f-v_0 = (4.1~m/s)-(-11.1~m/s) = 15.2~m/s$ We can use the change in velocity to find the change in the bird's momentum: $\Delta p = m~\Delta v$ $\Delta p = (0.031~kg)(15.2~m/s)$ $\Delta p = 0.4712~kg~m/s$ The impulse exerted on the bird is equal to the bird's change in momentum: $F~t = \Delta p$ $F = \frac{\Delta p}{t}$ $F = \frac{0.4712~kg~m/s}{0.071~s}$ $F = 6.64~N$ The average force exerted on the bird during the collision is $6.64~N$.