## College Physics (4th Edition)

$v = 4.2~m/s$
The impulse exerted on the ball by the cue stick is equal to the ball's change in momentum: $mv = F~t$ $v = \frac{F~t}{m}$ $v = \frac{(24~N)(0.028~s)}{0.16~kg}$ $v = 4.2~m/s$