College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 7 - Problems - Page 262: 4

Answer

$v = 4.2~m/s$

Work Step by Step

The impulse exerted on the ball by the cue stick is equal to the ball's change in momentum: $mv = F~t$ $v = \frac{F~t}{m}$ $v = \frac{(24~N)(0.028~s)}{0.16~kg}$ $v = 4.2~m/s$
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