Answer
$$P_{NOCl} = 28 \space atm$$
Work Step by Step
- The exponent of each pressure is equal to its balance coefficient.
$$K_P = \frac{P_{Products}}{P_{Reactants}} = \frac{P_{ NOCl } ^{ 2 }}{P_{ NO } ^{ 2 }P_{ Cl_2 }}$$
2. Solve for the missing concentration:
$$ \sqrt[2]{K_P \times P_{ NO } ^{ 2 }P_{ Cl_2 }}{} = P_{NOCl}$$
3. Evaluate the expression:
$$ P_{NOCl} = \sqrt[2]{(6.5 \times 10^{4}) \times {( 0.35 )^{ 2 }( 0.10 )}{}}$$
$$P_{NOCl} = 28 \space atm$$
