Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 17 - Problems - Page 770: 17.32

Answer

(a) 0.77 (b) $3.8 \times 10^{-58} $

Work Step by Step

(a) 1. Calculate $\Delta n$ (n is the amount of moles of gases): $$\Delta n = n_{products} - n_{reactants} = 2 - 2 = 0 $$ 2 . Calculate Kp: $$K_p = K_c(RT)^{\Delta n} = ( 0.77 )(0.0821 \times 1020. )^{ 0 }$$ $$K_p = 0.77 $$ (b) 1. Calculate $\Delta n$ (n is the amount of moles of gases): $$\Delta n = n_{products} - n_{reactants} = 2 - 3 = -1 $$ 2 . Calculate Kp: $$K_p = K_c(RT)^{\Delta n} = ( 1.8 \times 10^{-56} )(0.0821 \times 570. )^{ -1 }$$ $$K_p = 3.8 \times 10^{-58} $$
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