Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 17 - Problems - Page 770: 17.31

Answer

(a) $$K_p = 0.15 $$ (b) $$K_p = 3.6 \times 10^{-7} $$

Work Step by Step

(a) 1. Calculate $\Delta n$ (n is the amount of moles of gases): $$\Delta n = n_{products} - n_{reactants} = 2 - 1 = 1 $$ 2 . Calculate Kp: $$K_p = K_c(RT)^{\Delta n} = ( 6.1 \times 10^{-3} )(0.0821 \times 298 )^{ 1 }$$ $$K_p = 0.15 $$ (b) 1. Calculate $\Delta n$ (n is the amount of moles of gases): $$\Delta n = n_{products} - n_{reactants} = 2 - 4 = -2 $$ 2 . Calculate Kp: $$K_p = K_c(RT)^{\Delta n} = ( 2.4 \times 10^{-3} )(0.0821 \times 1000.)^{ -2 }$$ $$K_p = 3.6 \times 10^{-7} $$
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