Answer
(a) 49
(b) $1.0 \times 10^{12}$
Work Step by Step
(a)
1. Calculate $\Delta n$ (n is the amount of moles of gases):
$$\Delta n = n_{products} - n_{reactants} = 2 - 2 = 0 $$
2 . Calculate Kc:
$$K_c = \frac{K_p}{(RT)^{\Delta n}} = \frac{( 49 )}{(0.0821 \times 730. )^{ 0 }}$$
$$K_c = 49 $$
(b)
1. Calculate $\Delta n$ (n is the amount of moles of gases):
$$\Delta n = n_{products} - n_{reactants} = 2 - 3 = -1 $$
2 . Calculate Kc:
$$K_c = \frac{K_p}{(RT)^{\Delta n}} = \frac{( 2.5 \times 10^{10} )}{(0.0821 \times 500. )^{ -1 }}$$
$$K_c = 1.0 \times 10^{12} $$
