Chemistry: The Molecular Nature of Matter and Change 7th Edition

Published by McGraw-Hill Education
ISBN 10: 007351117X
ISBN 13: 978-0-07351-117-7

Chapter 17 - Problems - Page 770: 17.29

Answer

(a) $$K_c = 3.2 $$ (b) $$K_c = 28.5$$

Work Step by Step

(a) 1. Calculate $\Delta n$ (n is the amount of moles of gases): $$\Delta n = n_{products} - n_{reactants} = 1 - 2 = -1 $$ 2 . Calculate Kc: $$K_c = \frac{K_p}{(RT)^{\Delta n}} = \frac{( 3.9 \times 10^{-2} )}{(0.0821 \times 1000. )^{ -1 }}$$ $$K_c = 3.2 $$ (b) 1. Calculate $\Delta n$ (n is the amount of moles of gases): $$\Delta n = n_{products} - n_{reactants} = 1 - 1 = 0 $$ 2 . Calculate Kc: $$K_c = \frac{K_p}{(RT)^{\Delta n}} = \frac{( 28.5 )}{(0.0821 \times 500. )^{ 0 }}$$ $$K_c = 28.5$$
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