Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 720: 16.96c

Answer

Lewis acid: $Zn^{2+}$ Lewis base: $NH_3$

Work Step by Step

$NH_3$ has a free pair of electrons, and when 4 molecules of ammonia react with $Zn^{2+}$, the metal will receive these electrons. Since $NH_3$ donates a pair of electrons, it is the Lewis base. Since $Zn^{2+}$ receives pairs of electrons, it is the Lewis acid.
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