Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 720: 16.96b

Answer

Lewis Acid: $FeBr_3$ Lewis Base: $Br^-$

Work Step by Step

$Br^-$ has a pair of electrons free, so, when it reacts with $FeBr_3$, it will give that pair to the $Fe$ atom. Since $Br^-$ donates the pair of electrons, it is the Lewis base. Since $FeBr_3$ receives that pair, it is the Lewis acid.
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