Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 720: 16.95d


$H^+$: Lewis acid $N{H_2}^-$: Lewis base

Work Step by Step

The $N{H_2}^-$ has one pair of electrons free, so when it reacts with $HIO$, the $H^+$ will receive that pair. Since $N{H_2}^-$ donates one pair of electrons, it is the Lewis base. Since $H^+$ receive these electrons, it is the Lewis acid.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.