Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 720: 16.95c


Lewis acid: $BF_3$ Lewis base: $(CH_3)_3N$

Work Step by Step

Since "N" has 5 electrons in its valence shell, and it is doing only 3 ligations , there will be one pair of electrons disposable for donating. In the other side, $B$ has 3 electrons in its valence shell, and it is doing 3 ligations, so it is capable of receiving one pair, to have 8 electrons. The $(CH_3)_3N$ donates one pair of electrons, so it is the Lewis base, and the $BF_3$, who receives, is a Lewis acid.
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