Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 16 - Acid-Base Equilibria - Exercises - Page 720: 16.95b

Answer

$CN^-$ : Lewis Base $H^+$ : Lewis Acid

Work Step by Step

The $CN^-$ has a free pair of electrons, and when it reacts with $H_2O$, the $H^+$ will receive that pair. Since $CN^-$ donates one pair of electrons, it is the Lewis base. Since $H^+$ receives a pair of electrons, it is the Lewis acid.
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