Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Exercises - Page 40: 99

Answer

Using dimensional analysis gives: a.$ 1 km^{2} = 10^{6} m^{2} $ $195 / 10^{6} m^{2} = 1.95 \times 10^{-4} km^{2} $ b. $1 dm^{2} = 100 m^{2} $ $195 \times 100 = 1.95 \times 10^{4} dm^{2} $ c. $1 m^{2} = 10^{4} cm^{2} $ $ 195 \times 10^{4} cm^{2} = 1.95 \times 10^{6} cm^{2}$

Work Step by Step

Using dimensional analysis gives: a.$ 1 km^{2} = 10^{6} m^{2} $ $195 / 10^{6} m^{2} = 1.95 \times 10^{-4} km^{2} $ b. $1 dm^{2} = 100 m^{2} $ $195 \times 100 = 1.95 \times 10^{4} dm^{2} $ c. $1 m^{2} = 10^{4} cm^{2} $ $ 195 \times 10^{4} cm^{2} = 1.95 \times 10^{6} cm^{2}$
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