Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Exercises: 100

Answer

Using dimensional analysis gives: a. $1 km^{3} = 10^{9} m^{3} $ $115 / 10^{9} m^{2} = 1.15 \times 10^{-7} km^{2} $ b.$ 1 dm^{3} = 1000 m^{3} $ $115 x 1000 = 1.15 \times 10^{6} dm^{2} $ c.$ 1 m^{3} = 10^{6} cm^{3} $ $115\times10^{6} cm^{3} = 1.15\times10^{8} cm^{3}$

Work Step by Step

Using dimensional analysis gives: a. $1 km^{3} = 10^{9} m^{3} $ $115 / 10^{9} m^{2} = 1.15 \times 10^{-7} km^{2} $ b.$ 1 dm^{3} = 1000 m^{3} $ $115 x 1000 = 1.15 \times 10^{6} dm^{2} $ c.$ 1 m^{3} = 10^{6} cm^{3} $ $115\times10^{6} cm^{3} = 1.15\times10^{8} cm^{3}$
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