Answer
(a) \[\underline{\text{60}\text{.6}\ \text{in}}\]
(b)\[\underline{\text{3140}\ \text{g}}\]
(c)\[\underline{\text{3}\text{.7}\ \text{qt}}\]
(d)\[\underline{\text{4}\text{.29}\ \text{in}}\]
Work Step by Step
(a)
\[\begin{align}
& 154\ cm=\left( 154\ cm \right)\left( \frac{1\ in}{\text{2}\text{.54}\ \text{cm}} \right)\,\,\,\,\,\,\,\,\,\,\,\,\left[ \because \,1\,in\,=\,2.54\,\,cm \right] \\
& =60.6\ in
\end{align}\]
The given quantity\[\text{154}\ \text{cm }\] in \[\text{in}\text{.}\]is \[\underline{\text{60}\text{.6}\ \text{in}}\].
(b)
\[\begin{align}
& 3.14\ kg=\left( 3.14\ kg \right)\left( \frac{{{10}^{3}}\ \text{g}}{1\ kg} \right) \\
& =3140\ g
\end{align}\]
The given quantity\[\text{3}\text{.14}\ \text{kg}\] in \[\text{g}\]is \[\underline{\text{3140}\ \text{g}}\].
(c)
\[\begin{align}
& 3.5\ L=\left( 3.5\ L \right)\left( \frac{1.06\ \text{qt}}{1\ L} \right)\,\,\,\,\,\,\,\,\,\,\,\left[ \because \ 1L=\,1.06\ qt \right] \\
& =3.7\ qt
\end{align}\]
The given quantity\[\text{3}\text{.5}\ \text{L}\] in \[\text{qt}\]is \[\underline{\text{3}\text{.7}\ \text{qt}}\].
(d)
\[\begin{align}
& 109\ mm=\left( 109\ mm \right)\left( \frac{0.03937\ \text{in}}{1\ \text{mm}} \right)\,\,\,\,\left[ \because \,1mm\,=\,\,0.03937\,in \right] \\
& =4.29\ in
\end{align}\]
The given quantity\[\text{109}\ \text{mm }\]in \[\text{in}\text{.}\] is \[\underline{\text{4}\text{.29}\ \text{in}}\].
