Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Exercises - Page 40: 102

Answer

\[\underline{\text{42}\text{.15}%}\]

Work Step by Step

Convert \[\text{acres}\]to \[\text{f}{{\text{t}}^{\text{2}}}\] as follows: \[\begin{align} & 1\ \text{acre}=\text{43,560}\ \text{f}{{\text{t}}^{2}} \\ & \text{954}\ \text{million acres}=\left( 954\times {{10}^{6}} \right)\left( \text{43,560}\ \text{f}{{\text{t}}^{2}} \right) \end{align}\] Convert \[\text{m}{{\text{i}}^{2}}\]to \[\text{f}{{\text{t}}^{\text{2}}}\] as follows: \[\begin{align} & 1\ \text{mi}=\text{5280}\ \text{ft} \\ & 1\text{ m}{{\text{i}}^{2}}=\left( 1\ \text{m}{{\text{i}}^{2}} \right)\left( 1\ \text{m}{{\text{i}}^{2}} \right) \\ & =\left( \text{5280}\ \text{ft} \right)\left( \text{5280}\ \text{ft} \right) \\ & =27,878,400\ \text{f}{{\text{t}}^{2}} \end{align}\] Calculate the total area in \[\text{m}{{\text{i}}^{2}}\]as follows: \[\left( 954\times {{10}^{6}} \right)\left( 43,560\ \text{f}{{\text{t}}^{2}} \right)\left( \frac{1\ \text{m}{{\text{i}}^{2}}}{27,878,400\ \text{f}{{\text{t}}^{2}}} \right)=1.491\times 1{{0}^{6}}\ \text{m}{{\text{i}}^{2}}\] The total land area is \[3.537\times {{10}^{6}}\ \text{m}{{\text{i}}^{2}}\]. Calculate the percentage of land as follows: \[\begin{align} & P=\left( \frac{{{F}_{\text{A}}}}{{{T}_{\text{A}}}} \right)\left( 100 \right) \\ & =\left( \frac{1.491\times {{10}^{6}}\ \text{m}{{\text{i}}^{2}}}{3.537\times {{10}^{6}}\ \text{m}{{\text{i}}^{2}}} \right)\left( 100 \right) \\ & =42.15 \end{align}\] The percentage of land is \[\underline{\text{42}\text{.15}}\].
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.