# Chapter 5 - Exercises - Page 240d: 49

$Al_2O_3$: 101.96 g/mol $Na_3AlF_6$: 209.95 g/mol

#### Work Step by Step

$Al_2O_3$ : ( 26.98 $\times$ 2 )+ ( 16.00 $\times$ 3 )= 101.96 g/mol $Na_3AlF_6$ : ( 22.99 $\times$ 3 )+ ( 26.98 $\times$ 1 )+ ( 19.00 $\times$ 6 )= 209.95 g/mol

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