Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 5 - Exercises - Page 240d: 54

Answer

a. $$ 0.00455 \space mole$$ b. $$ 0.00322 \space mole$$ c. $$ 0.00704 \space mole$$

Work Step by Step

a. - Using the molar mass as a conversion factor, find the amount in moles: $$ 1.00 \space g \times \frac{1 \space mole}{ 219.88 \space g} = 0.00455 \space mole$$ b. $$ 1.00 \space g \times \frac{1 \space mole}{ 310.18 \space g} = 0.00322 \space mole$$ c. $$ 1.00 \space g \times \frac{1 \space mole}{ 141.96 \space g} = 0.00704 \space mole$$
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