Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 5 - Exercises - Page 240d: 50

Answer

$ CH_2FCF_3 $ : 102.04 g/mol $ CHClFCF_3 $ : 136.48 g/mol

Work Step by Step

$ CH_2FCF_3 $ : ( 1.008 $\times$ 2 )+ ( 12.01 $\times$ 2 )+ ( 19.00 $\times$ 4 )= 102.04 g/mol $ CHClFCF_3 $ : ( 35.45 $\times$ 1 )+ ( 1.008 $\times$ 1 )+ ( 12.01 $\times$ 2 )+ ( 19.00 $\times$ 4 )= 136.48 g/mol
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