Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 5 - Exercises - Page 240d: 62


a. $$1.10 \times 10^{22} \space atoms \space P$$ b. $$3.88 \times 10^{21} \space atoms \space P$$ c. $$4.24 \times 10^{21} \space atoms \space P$$

Work Step by Step

1. Using the answers from exercise 60: a. Each $P_4O_6$ has 4 $P$: $$2.74 \times 10^{21} \space molecules \space P_4O_6 \times \frac{4 \space atoms \space P}{1 \space molecule \space P_4O_6} = 1.10 \times 10^{22} \space atoms \space P$$ b. Each $Ca_3(PO_4)_2$ has 2 $P$: $$1.94 \times 10^{21} \space molecules \space Ca_3(PO_4)_2 \times \frac{2 \space atoms \space P}{1 \space molecule \space Ca_3(PO_4)_2} = 3.88 \times 10^{21} \space atoms \space P$$ c. Each $Na_2HPO_4$ has 1 $P$: $$4.24 \times 10^{21} \space molecules \space Na_2HPO_4 \times \frac{1 \space atom \space P}{1 \space molecule \space Na_2HPO_4} = 4.24 \times 10^{21} \space atoms \space P$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.