Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 5 - Exercises - Page 240d: 58

Answer

a. 619 g of $P$ b. 310. g of $P$ c. 155 g of $P$

Work Step by Step

a. - Each $ P_4O_6 $ has 4 P atoms, thus:$$ 5.00 \space mole \space P_4O_6 \times \frac{ 4 \space moles \ P }{1 \space mole \space P_4O_6 } = 20.0 \space moles \space P $$ - Calculate or find the molar mass for $ P $: $ P $ : 30.97 g/mol - Using the molar mass as a conversion factor, find the mass in g: $$ 20.0 \space mole \times \frac{ 30.97 \space g}{1 \space mole} = 619 \space g$$ b. - Each $ Ca_3(PO_4)_2 $ has 2 P atoms, thus:$$ 5.00 \space mole \space Ca_3(PO_4)_2 \times \frac{ 2 \space moles \ P }{1 \space mole \space Ca_3(PO_4)_2 } = 10.0 \space moles \space P $$ - Using the molar mass as a conversion factor, find the mass in g: $$ 10.0 \space mole \times \frac{ 30.97 \space g}{1 \space mole} = 310. \space g$$ c,- Each $ Na_2HPO_4 $ has 1 P atoms, thus:$$ 5.00 \space mole \space Na_2HPO_4 \times \frac{ 1 \space moles \ P }{1 \space mole \space Na_2HPO_4 } = 5.00 \space moles \space P $$ $$ 5.00 \space mole \times \frac{ 30.97 \space g}{1 \space mole} = 155 \space g$$
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