Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 5 - Exercises - Page 240c: 48

Answer

$8.3 \times 10^{-3} \space mol \space C $ $0.10 \space g \space C$

Work Step by Step

1. Use avogadro's number as a conversion factor to find the amount of moles: $$ 5.0 \times 10^{21} \space C \times \frac{1 \space mol}{6.02 \times 10^{23} \space C } = 8.3 \times 10^{-3} \space mol \space C $$ - Calculate or find the molar mass for $ C $: $ C $ : 12.01 g/mol 2. Using the molar mass as a conversion factor, find the mass in g: $$ 8.3 \times 10^{-3} \space mole \times \frac{ 12.01 \space g}{1 \space mole} = 0.10 \space g$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.