Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677c: 71


See proof below.

Work Step by Step

$Zn(OH)_2(s)\leftrightarrow Zn^{2+}(aq)+2OH^-(aq)$ $Ksp=[Zn^{2+}][OH^-]^2=3\dot{}10^{-17}$ $Zn^{2+}(aq)+4\ OH^-(aq)\leftrightarrow Zn(OH)_4^{2-}(aq)$ $Kf=[Zn(OH)_4^{2-}]/[Zn^{2+}][OH^-]=4.6\dot{}10^{17}$ $Zn(OH)_2(s)+2\ OH^-\leftrightarrow Zn(OH)_4^{2-}(aq)$ $K=Kf\dot{}Ksp=13.8$ Since K>1, this reaction is product favored.
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