Answer
$s=4.9\dot{}10^{-3}\ M$
Work Step by Step
With $pH=7.00$, $[OH^-]=10^{pKw-pH}=10^{-7}\ M$
$Ksp=[Fe^{2+}][OH^-]^2$
$4.9\dot{}10^{-17}=s\dot{}(10^{-7})^2$
$s=4.9\dot{}10^{-3}\ M$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677c: 61
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