Answer
$s=0.0347\ M$
Work Step by Step
With $pH=12.60$, $[OH^-]=10^{pKw-pH}=10^{-1.4}\ M$
$Ksp=[Ca^{2+}][OH^-]^2$
$5.5\dot{}10^{-5}=s\dot{}(10^{-1.4})^2$
$s=0.0347\ M$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677c: 62
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