Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505b: 48

Answer

$509.5\ g$

Work Step by Step

Molality: $\Delta T_f\rightarrow m=-10^{\circ}C\div(1.85\times-1.86^{\circ}C/m)=2.90\ m$ Number of moles: $2.90\ mol/kg\times 3.0\ kg=8.72\ mol$ Mass: $8.72\ mol\times 58.44\ g/mol=509.5\ g$
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